The following observations we're made during an experiment to find the value of g using simple pendulum l=90.0 cm
Time t for 20 vibrations =36 sec
Find percentage error in measurement of g given that T=2π√l/g length is being measured to an accuracy of 0.1 cm and time 0.2 sec
1
Expert's answer
2020-05-21T13:09:13-0400
We know that
T=2πgl⟹g=T24π2l.
T is equal to 36:20 = 1.8 seconds, so
g=1.824π2⋅0.9≈11.0m/s2. The uncertainty of period will be 200.2=0.01s.
Next, we should obtain the formula for calculating the percentage error (see part 5 in http://lectureonline.cl.msu.edu/~mmp/labs/error/e2.htm)
Comments
Leave a comment