Answer to Question #116760 in Mechanics | Relativity for sobia

Question

a car has a drag coefficient Cd=0.30, a frontal area of A = 1.9 meter square, a mass 1.2 tonnes and a coefficient of rolling resistance, Cr,= 0.012. it is travelling up a hill with a slope of 1 in 20 at 110 kph.
at what rate it is doing work against gravity(i.e. at what rate is it increasing its gravitational potential energy)?
Pg=_______kW.
(a 1:20 grade means that it rises 1m for every 20 m travelled along the road: sin(theta) = 1/20.)

Answer 1

$P_g=\frac{\Delta mgH }{\Delta t}=mg\frac{\Delta H}{\Delta t}$ as $\Delta H=v(\sin \theta) \Delta t$ then $P_g=mgV\sin\theta\approx1.2\sdot10^3\sdot9.8\sdot110\sdot3.6\sdot0.05\approx$

$\approx232.8\sdot10^3=233kW$