A 7.6 kg chair is pushed across a frictionless floor with a force of 42 N that is applied at an angle of 22° downward from the horizontal. What is the magnitude of the acceleration of the chair?
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Expert's answer
2010-12-05T06:15:47-0500
The horizontal projection of the force applied to the chair is Fh = Fcos (α) = 42 cos(22°) = 38.9 N. According ot the sewcond Newton's law, a = Fh/m = 38.9 / 7.6 = 5.11 m/s2
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