Question

A horizontal force of 24 Newton acts on a body of mass 5 kg to move it's on a horizontal surface with acceleration of 3 m per second squared then the magnitude of the friction Force =

Answer 1

given data:

$F_{horizontal} = 24 N$

$m = 5 Kg$

$a = 3 \frac {m} {sec^{2}}$

Net Horizontal Force

$F_{Net} = F_{horizontal} - F_{frictional}$

$F_{Net} = 24 - F_{frictional}$

Acceleration :

$a = \frac{F_{net}} {m}$

$a = \frac{24 - F_{frictional}} {m}$

$F_{frictional}=24- a\times m$

$F_{frictional}=24- a\times m$

$F_{frictional}=24- 3 \times 5$

$F_{frictional}= 9 N$