Solution.
a)"m=5.0kg;"
"g=9.8m\/s^2;"
"v_0=0;"
Since the forces of friction and resistance are absent, the unit moves under the action of gravity, the projection of which on the axis directed along the plane is equal to:
"F=mgsin\\alpha";
According to Newton's second law we have:
"ma=mgsin\\alpha;\\implies a=gsin\\alpha;"
"S=\\dfrac{v^2-v_0^2}{2a}; v_0=0 \\implies v^2=2aS;"
"h" -height of the plane, "\\alpha" - the angle of inclination of the plane;
"S=\\dfrac{h}{sin\\alpha};"
"v^2=2gsin\\alpha\\dfrac{h}{sin\\alpha}=2gh;"
"v=\\sqrt{2gh};"
"v=\\sqrt{2\\sdot9.8\\sdot h}=4.43\\sqrt{h} m\/s;"
Answer: "v=4.43\\sqrt{h} m\/s;"
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