Answer to Question #115854 in Mechanics | Relativity for Higgins
Calculate the work done by an applied force of 15 N [35° S of W] on an object that has moved 7.5 m [N 37° W].
1
2020-05-15T08:42:45-0400
"W=Fs\\cos{\\alpha}"
"W=(15)(7.5)\\cos{(37+35)}=34.8\\ J"
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