"Y=\\frac{TL}{\\Delta LA}"
As in both wire material is same hence the value of young's modulus will be same in both the cases
hence equating
"\\frac{200\\times3}{1.2\\times10^{-3}\\times A}=\\frac{200\\times6}{\\Delta L\\times A}"
"\\Delta L=2.4\\times10^{-3}m=2.4mm"
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