Question #115477

. A certain wire, 3 m long, stretches by 1.2 mm when under tension of 200 N. By how much does

an equally thick wire 6 m long, made of the same material and under the same tension, stretch?

A. 4.8 mm B. 2.4 mm C. 1.2 mm D. 0.6 mm

Expert's answer

Y=TLΔLAY=\frac{TL}{\Delta LA}


As in both wire material is same hence the value of young's modulus will be same in both the cases

hence equating

200×31.2×103×A=200×6ΔL×A\frac{200\times3}{1.2\times10^{-3}\times A}=\frac{200\times6}{\Delta L\times A}


ΔL=2.4×103m=2.4mm\Delta L=2.4\times10^{-3}m=2.4mm


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