K=0.5Mv2+0.5(4)Iω2
ω=rv
I=0.5mr2
K=0.5Mv2+0.5(0.5)(4)mv2The fraction of its total kinetic energy is due to rotation of the wheels about their axles is
0.5Mv2+0.5(0.5)(4)mv20.5(0.5)(4)mv2=M+2m2m=1000+2020=0.0196 As it can be seen that the radius of the wheels cancel out it is not required.
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