Question #114142
A 500g uniform sphere of 7cm radius spins at 30rev/sec on an axis through its center find its
A, KEr
B, angular momentum
C, radius of gyration
1
Expert's answer
2020-05-12T09:31:06-0400

The moment of inertia of a solid uniform sphere is


I=25mr2.I=\frac{2}{5}mr^2.

The kinetic energy of rotation is


KE=12Iω2=15mr2ω2=15mr2(2πn)2==17.4 J.KE=\frac{1}{2}I\omega^2=\frac{1}{5}mr^2\omega^2=\frac{1}{5}mr^2(2\pi n)^2=\\ =17.4\text{ J}.

The angular momentum is


L=Iω=4π5mnr2=0.185 Js.L=I\omega=\frac{4\pi}{5}mnr^2=0.185\text{ Js}.

The radius of gyration is


Rg=Im=r25=4.43 cm.R_g=\sqrt\frac{I}{m}=r\sqrt\frac{2}{5}=4.43\text{ cm}.

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