A ball of mass 0.1kg is thrown vertically upwards with initial velocity of 80m/s.Calculate the potential energy ( I) halfway up(11) at its maximum height. What is it kinetic energy as it leaves the ground?.
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Expert's answer
2020-05-05T18:41:36-0400
Let's calculate the maximum height
"H=v^2\/2g=320m"
PE=mgh=0.1*10*320=320 J
at halfway up PE will be half of max = 320/2=160 J
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