The normal force
N=mg−Fsin30°=10⋅9.81−70⋅sin30°=63.1NN=mg-F\sin30°=10\cdot 9.81-70\cdot \sin30°=63.1 NN=mg−Fsin30°=10⋅9.81−70⋅sin30°=63.1N
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