Question#11369
a train starting from rest picks up a speed of 20m/s in 200 seconds. It continues to move at the same speed for the next 500 seconds. It is then brought to rest next 100 seconds.
1. plot a speed time graph
2. calculate the rate of uniform acceleration.
3. calculate the distance covered by the train during retardation
4. calculate the average speed during retardation.
Solution:
Let:
v0=0v1=20m/st1=200sect2=500sect3=100sec
1

2.
a=t1v1−v0=20020=0.1m/sec2
3.
S=v1∗t3+2a1∗(t3)2=v1∗t3+2t3v0−v1∗(t3)2=v1∗t3−21v1∗t3=21v1∗t3S=2120∗100=1000m
4.
v(average)=2v1−v0=220=10m/sec