S=vt−1/2at2S=vt-1/2 at^2S=vt−1/2at2
V= velocity
So in the question, there is no velocity (V). Therefore v=0v=0v=0.
And we are using the minus(−-−) because it is decelerating.
t=0.5t=0.5t=0.5
a=5a=5a=5
Therefore S=0×0.5−1/2(5)(0.5)2S=0×0.5-1/2 (5) (0.5)^2S=0×0.5−1/2(5)(0.5)2 =−0.626m=-0.626m=−0.626m
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