Question

If the fuel consumption of a car, travelling at a steady 60 mph, is 20 mpg what is the power produced by the petrol being burnt in the engine? [Assume that the density of petrol is 0.84 kg/l and the heat of combustion of petrol is 47 302 kJ/kg]

Answer 1

$$\begin{array}{l} 60 \text{ mph} = 26.67 \text{ m/sec} \\ 20 \text{ mpg} = 8443.27 \text{ m/L} \end{array}$$

In 1 sec:

$$V(\text{fuel}) = \frac{26.67}{8443.27} = 0.0032 \text{ L}$$ $$Q = 0.0032 * 0.84 * 47302 = 125.5 \text{ kJ}$$ $$P = 125.5 \text{ kW}$$

Answer:

125.5 kW

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