Let's calculate μ\muμ =0.82×10−30.91=0.9×10−3\frac{0.82\times10^{-3}}{0.91}=0.9\times10^{-3}0.910.82×10−3=0.9×10−3
v=12lTμ=12×0.91T0.9×10−3v=\frac1{2l}\sqrt{\frac{T}{\mu}}=\frac{1}{2\times0.91}\sqrt{\frac{T}{0.9\times10^{-3}}}v=2l1μT=2×0.9110.9×10−3T
242×2×0.91×30=TT=13213.2T=174588654.24N242\times2\times0.91\times30=\sqrt T\\\sqrt T=13213.2\\T=174588654.24 N242×2×0.91×30=TT=13213.2T=174588654.24N
when string is divided into 3 segments then the frequency becomes 3 times of fundamental frequency
then the frequency is 3×242\times242×242 =726 Hz