C is the velocity of light in a vacuum equals to 3×108ms−1 .
If we are able to travel at a constant speed of 0.6C (which is greater than the escape velocity of earth,11.2kms-1: so escape is possible), the distance would be,
s=ut=0.60⋅(3⋅108ms−1)×(89×365×24×60×60s)=5.052×1017m=5.052×1014km
Comments