Question

A baseball of mass 0.239 kg sits on a tee. A kid's bat hits the ball and maintains contact for 0.005 seconds. The result is that the ball leaves the tee with a velocity of 11.03 m/s, traveling exactly horizontally.



Find the impulse given to the ball.

Answer 1

Impulse given to the ball$=$ change in momentum of the ball

So, impulse given$=m(v_2-v_1)=0.239\times(11.03-0)=2.63617Ns$