Question #108854

a child of mass 30kg skates down from the top of a ramp having a constant slope of 15degree. the childs speed increases from 1.5m/s to 3m/s as she reaches the bottom of the ramp. a force of kinetic friction of magnitude 50N opposes her motion. draw the appropriate force diagram and determine the length of the ramp. take g=10m/s²

Expert's answer


Hence the value of frictional force is given 50 N

let's calculate the force along the plane=mgsin15o = 77.6 N

acceleration down the plane = 77.6−5030=0.92m/s2\frac{77.6-50}{30}=0.92m/s^2

now applying

v2−u2=2aS32−1.52=2×0.92×SS=3.67mv^2-u^2=2aS\\3^2-1.5^2=2\times0.92\times S\\S=3.67m


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