On an interstate highway, you are traveling at 30 m/sec. The diameter of the wheels is 50 cm. How fast are the wheels rotating in revolutions/sec?
From,
"\\omega=\\frac{v}{r}"
where v is the velocity r is the radius and "\\omega" is the angular velocity
"\\omega=\\frac{v}{r}=\\frac{30}{0.25}=120rads^{-1}=>\\frac{120}{2\\pi}=19.09rev\/sec"
c. On your vacation, you visited several casinos in Las Vegas, and in one of them, you stopped by a roulette table. You observed that roulette wheel takes about 25 seconds to come to a stop, and it completed 40 revolutions in this time. How fast was it rotating at the very beginning before starting to slow down?
"\\theta=\\omega_0\\times t+\\frac{1}{2}\\alpha t^2 \\to(1)"
"\\omega=\\omega_0+{}\\alpha t\\to(2)"
where ,"\\theta" is the angle it rotated ,"\\omega_0" is the intial angular velocity and "\\alpha" is the angular acceleration
From 2,
"0=\\omega_0+\\alpha (25) => \\alpha=-\\frac{\\omega_0}{25}"
substituting to (1)
"40\\times2\\pi=\\omega_0\\times25+0.5\\times (-\\frac{\\omega_0}{25})\\times25^2"
solving this gives,
"\\omega_0=20.10rad\/s"
a. Provide a mathematical definition of momentum, and provide its unit in the
MKS system of units.
Momentum is a vector quantity that is the product of the mass and the velocity of an object or particle.
"Momentum (P) = Mass(m) \\times Velocity (V)"
units in MKS = "kg\\ ms^{-1}"
b. In a game of billiards, there are usually 11 identical balls. In this problem,
we concentrate on two of them. The first one is hit by the player and moves at a speed of 14 m/sec, and it collides with a second stationary ball. The two balls stick together. What is the speed of the balls after the collision?
since balls are identical the mass of the balls are equal,
"m_1=m_2=m"
From the momentum conservation principle, let "V_1" be the first ball speed and "V_2" be the speed of the two balls after collision.
"m_1 V_1=(m_1+m_2) V_2 \\\\\nmV_1=(2m)V_2\\\\\nV_2=\\frac{V_1}{2}=\\frac{14}{2}=7\\ m\/sec"
Comments
Leave a comment