Question

A direct compressive force of 240,000 N is applied to a solid piece of material of rectangular cross-section, 8 cm by 5 cm.

Answer 1

Given that,

A direct compressive force of 240,000 N is applied to a solid piece of material of rectangular cross-section, 8 cm by 5 cm.

Therefore the total cross sectional area = $8cm\times5cm=40cm^2$

Pressure acting on the solid piece of material by the compressive force is given by,

$P=\frac{F}{A}=\frac{240000}{40 \times 10^{-4}}$

$=6\times10^{7}Nm^{-2}$