a)Moment is equal
M1=mg⋅ON1=mg⋅Lsinα1=3⋅9.81⋅2⋅sin50=5.13NmM_1=m g \cdot {ON_1}=m g \cdot L \sin{\alpha_1 }=3 \cdot 9.81 \cdot 2 \cdot \sin{5^0 }=5.13 NmM1=mg⋅ON1=mg⋅Lsinα1=3⋅9.81⋅2⋅sin50=5.13Nm
b) When α2>α1\alpha_2 > \alpha_1α2>α1 then ON2>ON1ON_2>ON_1ON2>ON1 as M2=mg⋅ON2M_2= mg \cdot ON_2M2=mg⋅ON2 then M2>M1M_2>M_1M2>M1
That is, with increasing angle, the moment increases
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