Question

golfer hits a 46 g golfball with an initial velocity of 54 m/s at 25°. What are the horizontal and vertical components of momentum imparted to the ball?

Answer 1

The momentum is

$$\vec{p}=m\vec{v}.$$

The horizontal component:

$$p_x=mv_x=mv\text{ cos}\alpha=\\=46\cdot10^{-3}\cdot54\text{ cos}25^\circ=2.3\text{ kg}\cdot\text{m/s}.$$

The vertical component:

$$p_y=mv_y=mv\text{ sin}\alpha=\\=46\cdot10^{-3}\cdot54\text{ sin}25^\circ=2.3\text{ kg}\cdot\text{m/s}.$$