Question

A car of mass 1.6 t travels at a constant speed of 72 km/h around a horizontal curved road with radius of curvature 190 m.
Draw a free-body diagram. What is the minimum value of μs between the road and the tyres that will prevent slippage?

Answer 1

$$F_s = μ_sN =\frac{ mv^2}{r}$$

$$W=N=mg$$

$$μ_smg=\frac{ mv^2}{r}$$

$$μ_s=\frac{ v^2}{gr}=\frac{(\frac{ 72}{3.6})^2}{(9.8)(190)}=0.21$$