Question

A horizontal force of 0.5N acts on a body of mass 0.2kg. there is frictional force of 0.2 opposing the first force. What acceleration will be produced?

Answer 1

The net force on a body

$$F_{net}=F-F_f=0.5\:\rm N-0.2\: N=0.3\: N.$$

The acceleration of the body

$$a=\frac{F_{net}}{m}=\frac{0.3\:\rm N}{0.2\:\rm kg}=1.5\:\rm N.$$