Taking moment around point A for the stability of the bar,
mgsin(45)×AB=Tsin(45)×AC53g×sin(45)×5×sin(45)×8.4T=61.89Nmg\sin(45) \times AB=T\sin(45) \times AC\\ 53g\times\sin(45)\times 5\times \sin(45) \times8.4\\ T=61.89Nmgsin(45)×AB=Tsin(45)×AC53g×sin(45)×5×sin(45)×8.4T=61.89N
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