Question #1069
A 224 kg crate is pushed horizontally with a force of 710 N. If the coefficient of friction is 0.25, calculate the acceleration of the crate.
Expert's answer
According the Second Newton's law
ma = F - μ mg;
a = F/m - μ g = 710/224 - 0.25* 10 = 0.67 m/s2
ma = F - μ mg;
a = F/m - μ g = 710/224 - 0.25* 10 = 0.67 m/s2
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