A 3kg box slides down a 30.0 degree ramp with an acceleration of 1.4 m/sec^2. Determine the coefficient of kinetic friction between the box and the ramp.
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Expert's answer
2010-11-19T07:55:43-0500
Let's write the Second Newton's Law for the box: mg sin(30) - μ N = ma N = mg cos(30); mg sin(30) - μ mg cos(30) = ma; μ = (g sin(30) -a )/(g cos(30)) = 0.41
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