MMM =4 kg - mass of machine
mmm = 45 g - mass of bullet
vvv = 100 m/s - speed of bullet
v′v'v′ - recoil speed of machine gun
Law of conservation of momentum:
0=mv−Mv′0=mv-Mv'0=mv−Mv′
Then v′=mv/M=0.045∗100/4=1.125v'=mv/M=0.045*100/4=1.125v′=mv/M=0.045∗100/4=1.125 m/s
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