Question

A dog sits 1.40 m from the center of a merry- go-round with an angular speed of 1.94 rad/s. If the magnitude of the force that maintains
the dog’s circular motion is 36.2 N, what is the dog’s mass?
Answer in units of kg.

Answer 1

$$F=m\omega^2r$$

$$36.2=(1.94)^2(1.4)m$$

$$m=6.87\ kg$$