We need to find the speed of the water as it flows through the smaller pipe.
Solution:
Given,
Area of the first pipe = "13 \\space in^2"
Speed of the first pipe = "12 \\space ft\/s"
Are of the small pipe = "3.1 \\space in^2"
By conservation of mass and continuity equation
Area of first pipe "\\times" velocity of the First Pipe = Area of small pipe "\\times" velocity of small pipe
"13 \\times 12 = 3.1 \\times Velocity \\space of \\space small \\space pipe"
velocity of small pipe
"= \\frac {13 \\times 12}{3.1} = \\frac {156}{3.1} =50.32 \\space ft\/s"Answer:
speed of the water flowing through the smaller pipe ="50.32 ft\/s"
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