Question #106568
In a hydraulic press, the area of the small piston is 25.0 cm2 and the area of the large piston is 325 cm2. If a force of 75.0 N is exerted on the small piston, find the weight of the object that can be lifted by the large piston.
1
Expert's answer
2020-03-30T08:07:26-0400

We use Pascal’s principle F1A1=F2A2;F2=F1×A2A1;F2=75N×325cm225cm2;F2=975N;Answer:975N\frac {F_1}{A_1}=\frac {F_2}{A_2}; F_2=F_1\times\frac{A_2}{A_1}; F_2=75 N \times \frac{325 {cm^2}}{25 {cm^2}}; F_2=975 N; Answer: 975 N


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