A 50kg sled is pulled by a rope at an angle of 30 degrees above the horizontal with a force of 35 N. This force is just sufficient to keep the sled moving t a constant speed . What is the coefficient of sliding friction for the sled-snow surface?
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Expert's answer
2010-11-19T08:44:24-0500
Let's write the Second Newton's law for the sled which is moving with a constant speed: F cos(α) =μ mg; μ = F cos(α) / mg =35 cos(30) / (50*10) = 0.06
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