Question

Calculate the work done by a 14N force at 40° to the horizontal to move a 505g box a horizontal distance of 40m across a rough floor at a constant speed of 0.5m/s.

Answer 1

$F=14$ $N$

$\alpha=40^o$

$m=505$ $g$

$S=40$ $m$

$v=0.5$ $m/s$

Answer:

$A=FScos(\alpha)=14*40*cos(40^o)=498.985$ $J$