Question

calculate the horizontal component of the initial velocity of the shot when the shot is a metal ball of mass 4.0 kg and the angle of projection for a particular throw is 40 degree

Answer 1

The horizontal component of the initial velocity is

$v_x=v_0\cdot \cos 40°$ .

Assuming that $v_0=5$ $m/s$

We have

$v_x=v_0\cdot \cos 40°=5\cdot \cos 40°=3.83$ $m/s$