Answer to Question #105633 in Mechanics | Relativity for Titomi

Question

In a nuclear plant, the final mass of the products is 6.32×10^-27kg, while the initial mass of the reactant is 6.30×10^-27kg, the energy released in the process is (speed of light in vacuum 3.0×10^8m/s, 1eV = 1.6×10^-19J)

Answer 1

Energy released =$\Delta m c^2$

Here $\Delta m =6.32\times10^{-27}-6.30\times10^{-27}=0.02\times10^{-27} kg =2\times10^{-29}kg$

substituting the value of $\Delta m$ and c in the above formula we get

$E=2\times10^{-29}\times(3\times10^8)^2=18\times10^{-13} J$