Answer to Question #105633 in Mechanics | Relativity for Titomi

Question #105633
In a nuclear plant, the final mass of the products is 6.32×10^-27kg, while the initial mass of the reactant is 6.30×10^-27kg, the energy released in the process is (speed of light in vacuum 3.0×10^8m/s, 1eV = 1.6×10^-19J)
1
Expert's answer
2020-03-17T09:21:53-0400

Energy released ="\\Delta m c^2"

Here "\\Delta m =6.32\\times10^{-27}-6.30\\times10^{-27}=0.02\\times10^{-27} kg =2\\times10^{-29}kg"

substituting the value of "\\Delta m" and c in the above formula we get

"E=2\\times10^{-29}\\times(3\\times10^8)^2=18\\times10^{-13} J"


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