A stone falls from a tower, height 100m.At same time another stone through with 4.5m\s velocity.when they meet and which height.
A stone falls from a tower, height 100m. At same time another stone through with 4.5m\s velocity. when they meet and which height.
The answer depends on a direction the second stone was thrown.
Anyhow, the first stone flight time is
t = √(2H/g) = √(2·100/9.8) ≈ 4.5175 s.
If the second stone was thrown horizonatally down, it reached the ground earlier then the first one, so the meeting time is 4.5175s and meeting height is 0m.
Need a fast expert's response?
Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!