Answer to Question #105264 in Mechanics | Relativity for let me know

Question #105264
[img]https://upload.cc/i1/2020/03/12/It65bk.jpg[/img]



d8 is 4
1
Expert's answer
2020-03-13T11:23:52-0400

(a)

"\\frac{mu^2}{2}=\\frac{mv^2}{2}+\\mu_km_1gl"


"v=\\sqrt{\\frac{2}{m}(\\frac{mu^2}{2}-\\mu_km_1gl)}="


"\\sqrt{\\frac{2}{0.05}(\\frac{0.05\\cdot 858^2}{2}-0.4\\cdot 6\\cdot 9.8\\cdot 0.1)}=857.94" "m\/s"


(b)


  • there is no energy loss for the deformation of the block 1
  • there is no conversion of mechanical energy into thermal energy



(c)


"mv=(m_2+m)V \\to V=\\frac{mv}{m_2+m}=\\frac{0.05\\cdot 857.94}{8+0.05}=5.33" "m\/s"


(d)


"\\frac{(m_2+m)V^2}{2}=\\frac{kd^2}{2}+\\mu_k(m_2+m)gd"


"d\\approx0.231" "m"







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