Answer to Question #105264 in Mechanics | Relativity for let me know

Question

[img]https://upload.cc/i1/2020/03/12/It65bk.jpg[/img]



d8 is 4

Answer 1

(a)

$\frac{mu^2}{2}=\frac{mv^2}{2}+\mu_km_1gl$

$v=\sqrt{\frac{2}{m}(\frac{mu^2}{2}-\mu_km_1gl)}=$

$\sqrt{\frac{2}{0.05}(\frac{0.05\cdot 858^2}{2}-0.4\cdot 6\cdot 9.8\cdot 0.1)}=857.94$ $m/s$

(b)

• there is no energy loss for the deformation of the block 1
• there is no conversion of mechanical energy into thermal energy

(c)

$mv=(m_2+m)V \to V=\frac{mv}{m_2+m}=\frac{0.05\cdot 857.94}{8+0.05}=5.33$ $m/s$

(d)

$\frac{(m_2+m)V^2}{2}=\frac{kd^2}{2}+\mu_k(m_2+m)gd$

$d\approx0.231$ $m$