In a closed tube, the resonance occurs at the following points from the opened top of the tube:
L1=4fv=0.25 m,L2=4f3v=0.75 m,L3=4f5v=1.25 m.
But the actual (effective) length of the tube is 1.2 m. Therefore, the resonance will occur at
d=L−L2=1.2−0.75=0.45 m.
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