Question #104836
Two hockey players push off from a clinch, recoiling from rest. Jean-Claude has an inertia that is 60% greater than Pierre's inertia. After they push off and move across the ice in opposite directions, they lose kinetic energy at the same rate until they come to a stop.

1.What is the ratio of the distances which players traveled?
1
Expert's answer
2020-03-10T11:27:07-0400
m2=1.6m1m_2=1.6m_1

From the conservation of momentum:


m1v1=m2v2v1=1.6v2m_1v_1=m_2v_2\to v_1=1.6v_2

K10=0.5m1v12K_{10}=0.5m_1v_1^2

K20=0.5m2v22=K101.6=0.625K10K_{20}=0.5m_2v_2^2=\frac{K_{10}}{1.6}=0.625K_{10}

dJCdP=K20K10=0.625\frac{d_{JC}}{d_P}=\frac{K_{20}}{K_{10}}=0.625


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