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Question #104549
https://upload.cc/i1/2020/03/03/UFc9i5.jpg
d8 is 4
Expert's answer
i)
u
=
d
T
=
40
+
80
+
60
5
+
4
+
3
=
15
m
s
u=\frac{d}{T}=\frac{40+80+60}{5+4+3}=15\frac{m}{s}
u
=
T
d
=
5
+
4
+
3
40
+
80
+
60
=
15
s
m
ii)
s
=
(
40
cos
30
i
−
40
sin
30
j
)
+
80
i
+
+
(
60
cos
50
i
+
60
sin
50
j
)
\bold{s}=(40\cos{30}\bold{i}-40\sin{30}\bold{j})+80\bold{i}+\\+(60\cos{50}\bold{i}+60\sin{50}\bold{j})
s
=
(
40
cos
30
i
−
40
sin
30
j
)
+
80
i
+
+
(
60
cos
50
i
+
60
sin
50
j
)
s
=
(
153
i
+
26
j
)
m
\bold{s}=(153\bold{i}+26\bold{j})\ m
s
=
(
153
i
+
26
j
)
m
iii)
v
=
(
153
i
+
26
j
)
5
+
4
+
3
=
(
12.8
i
+
2.2
j
)
m
s
\bold{v}=\frac{(153\bold{i}+26\bold{j})}{5+4+3}=(12.8\bold{i}+2.2\bold{j})\frac{m}{s}
v
=
5
+
4
+
3
(
153
i
+
26
j
)
=
(
12.8
i
+
2.2
j
)
s
m
iv)
v
=
12.
8
2
+
2.
2
2
=
12.9
m
s
v=\sqrt{12.8^2+2.2^2}=12.9\frac{m}{s}
v
=
12.
8
2
+
2.
2
2
=
12.9
s
m
θ
=
arctan
2.2
12.8
=
9.6
°
\theta=\arctan{\frac{2.2}{12.8}}=9.6\degree
θ
=
arctan
12.8
2.2
=
9.6°
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on Dec 2023
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