2020-03-04T10:09:40-05:00
https://upload.cc/i1/2020/03/03/UFc9i5.jpg
d8 is 4
1
2020-03-06T10:27:55-0500
i)
u = d T = 40 + 80 + 60 5 + 4 + 3 = 15 m s u=\frac{d}{T}=\frac{40+80+60}{5+4+3}=15\frac{m}{s} u = T d = 5 + 4 + 3 40 + 80 + 60 = 15 s m
ii)
s = ( 40 cos 30 i − 40 sin 30 j ) + 80 i + + ( 60 cos 50 i + 60 sin 50 j ) \bold{s}=(40\cos{30}\bold{i}-40\sin{30}\bold{j})+80\bold{i}+\\+(60\cos{50}\bold{i}+60\sin{50}\bold{j}) s = ( 40 cos 30 i − 40 sin 30 j ) + 80 i + + ( 60 cos 50 i + 60 sin 50 j )
s = ( 153 i + 26 j ) m \bold{s}=(153\bold{i}+26\bold{j})\ m s = ( 153 i + 26 j ) m
iii)
v = ( 153 i + 26 j ) 5 + 4 + 3 = ( 12.8 i + 2.2 j ) m s \bold{v}=\frac{(153\bold{i}+26\bold{j})}{5+4+3}=(12.8\bold{i}+2.2\bold{j})\frac{m}{s} v = 5 + 4 + 3 ( 153 i + 26 j ) = ( 12.8 i + 2.2 j ) s m
iv)
v = 12. 8 2 + 2. 2 2 = 12.9 m s v=\sqrt{12.8^2+2.2^2}=12.9\frac{m}{s} v = 12. 8 2 + 2. 2 2 = 12.9 s m
θ = arctan 2.2 12.8 = 9.6 ° \theta=\arctan{\frac{2.2}{12.8}}=9.6\degree θ = arctan 12.8 2.2 = 9.6°
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