Answer to Question #103754 in Mechanics | Relativity for Jackson Scott

Question #103754
M=0.500kg on level table, Fs= 0.600. Three strings tide together in a knot, 1 attach to mass, 2 30°above horizontal attached to wall, 3 hangs M2 vertically what is the Maximum weight of M2 for M1 & 2 to remain in equilibrium
1
Expert's answer
2020-02-26T10:13:36-0500

For the equilibrium:


"m_2g=T"

"N=m_1g-T\\sin 30=m_1g-0.5T"

"T=T\\cos{30}+\\mu_sN=T\\cos{30}+\\mu_s(m_1g-0.5T)"

"T=T\\cos{30}+\\mu_s(m_1g-0.5T)"

"T=T\\cos{30}+0.6((0.5)(9.8)-0.5T)"



Maximum weight of M2 for M1 & 2 to remain in equilibrium



"T=6.77\\ N"


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