Question

An alpha particle having a speed of 1.0X6^6ms^-1 collides with the stationary proton which gain an initial speed of 1.60X10^6ms^-1 in the direction of an alpha. 1. What is the speed of 2particle immediately after the collission? 2. How much kinetic energy is gain by the proton after the collission?

Answer 1

1) From the conservation of momentum:

$$Mv=mu-Mv'$$

$$v'=\frac{m}{M}u-v$$

$$v'=\frac{1.67\cdot 10^{-27}}{‎6.64\cdot 10^{-27}}1.6\cdot 10^6-1.0\cdot 6^6$$

$$v'=3.56\cdot 10^5\frac{m}{s}$$

2)

$$K_p=0.5mu^2$$

$$K_p=0.5(1.67\cdot 10^{-27})(1.6\cdot 10^6)^2=2.14\cdot 10^{-15}\ J$$