m=2.50kg
d=2.20m
F=16.0N
α=25.0°
(a)
W=F⋅d⋅cosα=16⋅2.2⋅cos25°=31.9J
(b) The normal force is perpendicular to the displacement of the block. So,
WN=FN⋅d⋅cosα=FN⋅d⋅cos90°=0J
(c) Gravity force is also perpendicular to the displacement. So,we have
WG=FG⋅d⋅cosα=FG⋅d⋅cos90°=0J
(d)
WΣ=W+WN+WG=31.9+0+0=31.9J
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