Answer to Question #103542 in Mechanics | Relativity for Valentine Agun

Question #103542
The coefficient of static friction between the 3.00-kg crate and the 35.0° incline of Figure P4.31 is 0.300. What minimum force SF must be applied to the crate perpendicular to the incline to prevent the crate from sliding down the incline?
1
Expert's answer
2020-02-24T10:18:27-0500
N=mgcos35+FN=mg\cos{35}+F

Ff=μN=μ(mgcos35+F)F_f=\mu N=\mu (mg\cos{35}+F)

For the equilibrium:


0.3((3)(9.81)cos35+F)=(3)(9.81)sin350.3 ((3)(9.81)\cos{35}+F)=(3)(9.81) \sin{35}

F=32.2 NF=32.2\ N


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Comments

Lulu
12.11.20, 16:42

Very helpful

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