Answer to Question #103209 in Mechanics | Relativity for Alan

Question

Calculate the depth in the ocean at which the
pressure is three times atmospheric pressure.
Atmospheric pressure is 1.013 × 105 Pa. The
acceleration of gravity is 9.81 m/s
2
and the
density of sea water is 1025 kg/m3
.
Answer in units of m.

Answer 1

$p=p_0+\rho gh$

$3p_0=p_0+\rho gh \to h=\frac {2p_0}{\rho h}=\frac{2\cdot101325}{1025\cdot 9.81}=20.1m$