Question

The bulk modulus of a block of copper is 1.3 GPa. When a pressure of 1.8 MPa is applied to the 1.0 m^3 block, its volume decreases by how much?

Answer 1

$K=-V_0\frac{\Delta p}{\Delta V}$

Given.

$K=1.3 GPa$

$p_0=101325 Pa$

$p=1.8 MPa$

$V_0=1 m^3$

$\Delta V=-V_0\frac{p-p_0}{K}=-1\cdot \frac{1800000-101325}{1.3\cdot10^9}\approx-0.00131 m^3=-1310 cm^3$