Answer to Question #102690 in Mechanics | Relativity for sakshi

Question #102690
A centrifuge in the shape of a uniform cylinder of radius 20 cm and mass 10 kg cylinder is spinning about its axis at a speed of 50,000 rpm. Determine the torque that must be applied in order to bring the centrifuge to a stop in 20 s. Calculate the power dissipated.
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Expert's answer
2020-02-20T09:29:21-0500

Torque:

τ=Iα=Iωt=0.5mr2ωt\tau=I\alpha=I\frac{\omega}{t}=0.5mr^2\frac{\omega}{t}τ=0.5(10)(0.2)22π(50000)2060=52.36 Nm\tau=0.5(10)(0.2)^2\frac{2\pi (50000)}{20\cdot 60}=52.36\ Nm

Power:


P=Tω=52.362π(50000)60=274000 W=274 kWP=T\omega=52.36\frac{2\pi (50000)}{ 60}=274000\ W=274\ kW


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