Question

If you drop an aspirin from rest and it takes 0.35 seconds to hit the table, how high above the table was the aspirin when it was released?

a.
1.72 m

b.
1.2 m

c.
0.6 m

d.
3.43 m

Answer 1

$S=v_0 \cdot t+a \cdot t^2$,

where $S$ is a displacement, $v_0$ - initial speed, $t$ - time, $a$ - acceleration (in considered case acceleration equals to the gravitational acceleration $a=g \approx 9.8 \; m/s^2$ ).

$S=0 \cdot 0.35+9.8 \cdot 0.35^2 \approx 1.2 \; m$

Answer: b. 1.2 m.