Question

The equation of transverse wave on a rope is

y(x, t) = 7 sin (4.0t − 0.02x)

where y and x are measured in cm and t is expressed in second. Calculate the

maximum speed of a particle on the rope. (5)

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Answer 1

maximum speed V_max =Aw where A - amplitude, w-frequency. From y(x,t)=7sin(4.0t-0.02x) , A=0.07 m , w=4.0 => V_max=0.07*4=0.28