Answer to Question #102527 in Mechanics | Relativity for desire

Question

A pebble is shot vertically at 28m/s ignoring air resistance. What height will the pebble reach?

Answer 1

From the conservation of energy:

$$0.5mv^2=mgh$$

$$h=\frac{v^2}{2g}=\frac{28^2}{2(9.8)}=40\ m$$